Когда я получаю длинное соединение с pdo, выполняю операцию вставки транзакции, я вручную отключаюсь или mysql автоматически отключается на некоторое время, я повторно получаю транзакцию выполнения соединения, которая продолжит выполнять последнюю операцию, вызывая вставку данных в база данных
mysql5.7
$pdoOptions = [
PDO::ATTR_TIMEOUT => 30,
PDO::ATTR_PERSISTENT => true,
];
$dsn = "mysql:host=mysql;port=3306;dbname=test;charset=utf8";
$connection = new PDO($dsn, 'root', 'root', $pdoOptions);
try{
$connection->beginTransaction();
$smtm = $connection->prepare("INSERT INTO classic(class_name)VALUES(:name)");
$smtm->bindValue(':name',飇');
$smtm->execute();
throw new Exception('Manual exception throwing');
$connection->commit();
}catch (Throwable $e){
echo ('Received exception information thrown:' . $e->getMessage());
echo "
";
try{
$connection->rollBack();
}catch (Throwable $e2){
echo ('Exception fired by rollback:' . $e->getMessage());
echo "
";
}
}
$connection = null;
echo 'connection Set to null, the current pdo link is broken'
echo "
";
$connection = new PDO($dsn, 'root', 'root', $pdoOptions);
echo 'Set to null and get the new link again to determine whether it is in the transaction:' .($connection->inTransaction()?'是':'否');
echo "
";
$connection->beginTransaction();
echo 'BeginTransaction to start a transaction'
echo "
";
try{
echo('New link transaction open status:'.($connection->inTransaction()?'yes':'no'));
echo "
";
$smtm = $connection->prepare("INSERT INTO classic(class_name)VALUES(:name)");
echo ('Current linked transaction status after connection->prepare() execution:'.($connection->inTransaction()?'yes':'no'));
echo "
";
$smtm->bindValue(':name',餶');
// echo $smtm->queryString;
$smtm->execute();
echo 'After the new link is obtained, an exception is thrown and the second execution fails to roll it back'
echo "
";
throw new Exception('The second transaction executes, throwing an exception manually');
$connection->commit();
}catch (Throwable $e){
echo ('Get new link exception catch:' . $e->getMessage());
echo "
";
try{
$connection->rollBack();
}catch (Throwable $e2){
echo ('The exception triggered by the second rollback:' . $e2->getMessage());
echo "
";
}
}
Таблица
CREATE TABLE `classic` (
`id` INT(11) NOT NULL AUTO_INCREMENT,
`class_name` VARCHAR(50) NULL DEFAULT NULL,
PRIMARY KEY (`id`)
)
COLLATE='utf8_general_ci'
ENGINE=InnoDB
AUTO_INCREMENT=1;
Этот код заставляет базу данных фактически вставить часть данных
Всего 1 ответ
очень странно, вторая транзакция как-то находит способ совершить. измените имя второго соединения на $ connection1 и запустите.
<?php
namespace app;
ini_set('display_errors', 1);
$pdoOptions = [
PDO::ATTR_TIMEOUT => 30,
PDO::ATTR_PERSISTENT => true,
];
$dsn = "mysql:host=localhost;port=3306;dbname=test;charset=utf8";
$connection = new PDO($dsn, 'root', 'infiniti', $pdoOptions);
try{
$connection->beginTransaction();
$smtm = $connection->prepare("INSERT INTO classic(class_name)VALUES(:name)");
$smtm->bindValue(':name',飇');
$smtm->execute();
throw new Exception('Manual exception throwing');
$connection->commit();
}catch (Exception $e){
echo ('Received exception information thrown:' . $e->getMessage());
echo "
";
try{
$connection->rollBack();
}catch (Exception $e2){
echo ('Exception fired by rollback:' . $e->getMessage());
echo "
";
}
}
$connection = null;
echo 'connection Set to null, the current pdo link is broken'
echo "
";
$connection1 = new PDO($dsn, 'root', 'infiniti', $pdoOptions);
echo 'Set to null and get the new link again to determine whether it is in the transaction:' .($connection1->inTransaction()?'yes':'no');
echo "
";
$connection1->beginTransaction();
echo 'BeginTransaction to start a transaction'
echo "
";
try{
echo('New link transaction open status:'.($connection1->inTransaction()?'yes':'no'));
echo "
";
$smtm = $connection1->prepare("INSERT INTO classic(class_name)VALUES(:name)");
echo ('Current linked transaction status after connection->prepare() execution:'.($connection1->inTransaction()?'yes':'no'));
echo "
";
$smtm->bindValue(':name',餶');
// echo $smtm->queryString;
$smtm->execute();
echo 'After the new link is obtained, an exception is thrown and the second execution fails to roll it back'
echo "
";
throw new Exception('The second transaction executes, throwing an exception manually');
echo 'wowowowo'."
";
$connection1->commit();
}catch (Exception $e){
echo ('Get new link exception catch:' . $e->getMessage());
echo "
";
try{
$connection1->rollBack();
}catch (Exception $e2){
echo ('The exception triggered by the second rollback:' . $e2->getMessage());
echo "
";
}
}
?>